tentukan penyelesaian dari
sin (x-30°)=sin 90°,0°<=×<=360°
sin (x-30°)=sin 90°,0°<=×<=360°
Jawaban:
K1 : x - 30° = 90° + k. 360°
k0 = x - 30° = 90° + 0. 360°
x = 90° + 30°
x = 120° (M)
k1 = x - 30° = 90° + 1.360°
x = 120° + 360°
x = 480°(TM)
K2 : x - 30° = (180° - 90°) + k.360°
k0 = x - 30° = 90° + 0.360°
x = 120° (M)
k1 = x - 30° = 90° + 1. 360°
x = 120° + 360°
x = 480° (TM)
HP : {120°}
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