buktikan bahwa 2+4+6+6+8+10+...+2n=n(n+1)
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InDUksi Matematika
i.n = 1
ii.n = k
iii, n = (k+1)
Penjelasan dengan langkah-langkah:
buktikan bahwa 2+4+6+6+8+10+...+2n=n(n+1)
i. n= 1 --> 2(1) = 1(1+1)
2= 2
ii. n = k --> 2 + 4 + 6 + 8 +10 + . . . + 2k = k (k+1)
iii. n = k + 1
2 + 4 + 6 + 8 +10 + . . . + 2k+ 2(k+1) = (k +1) (k+1+1)
k(k+1) + 2(k+1) = (k+1)(k+2)
(k+1)(k+2) = (k+1)(k+2)
ruas kiri = ruas kanan
terbukti
